Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>
void classify_string(const char *str) {
    uint8_t i = 0;
    uint8_t has_alpha = 0, has_digit = 0, has_other = 0;

    if (str[0] == '\0') {
        printf("MIXED\n");
        return;
    }

    while (str[i]) {
        char ch = str[i];
        if ((ch >= 'A' && ch <= 'Z') || (ch >= 'a' && ch <= 'z')) {
            has_alpha = 1;
        } else if (ch >= '0' && ch <= '9') {
            has_digit = 1;
        } else {
            has_other = 1;
        }
        i++;
    }

    if (has_other || (has_alpha && has_digit)) {
        printf("MIXED\n");
    } else if (has_alpha) {
        printf("ALPHABETIC\n");
    } else if (has_digit) {
        printf("NUMERIC\n");
    } else {
        printf("MIXED\n");
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

 

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Input

123456

Expected Output

NUMERIC