Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    int8_t alpha = 0, numeric = 0, mixed = 0;

    if(str[0] == '\0'){
        printf("MIXED");
        return;
    }

    while(*str != '\0'){
        if(*str >= '0' && *str<= '9'){
            numeric++;
        }
        else if((*str >= 'a' && *str <= 'z') || (*str >= 'A' && *str <= 'Z')){
            alpha++;
        }
        else{
            mixed++;
        }

        str++;
    }


    if(alpha && !numeric && !mixed){
        printf("ALPHABETIC");
    }
    else if(!alpha && numeric && !mixed){
        printf("NUMERIC");
    }
    else{
        printf("MIXED");
    }

}


int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach