Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    int i=0;     
    int is_digit = 0;
    int is_alpha = 0;

    if(str[i] == '\0')
    {
        printf("MIXED (empty string is considered mixed");
        return;
    }

    while(str[i] != '\0')
    {
        char ch = str[i];

        if(ch>='0' && ch<='9')
        {
            is_digit = 1;
        }
        else if(ch>='A' && ch<='Z' || ch>='a' && ch<='z')
        {
            is_alpha = 1;
        }
        else
        {
            printf("MIXED");
            return;
        }
        i++;
    }

    if(is_digit && is_alpha)
    {
        printf("MIXED");
    }
    else if(is_digit)
    {
        printf("NUMERIC");
    }
    else if(is_alpha)
    {
        printf("ALPHABETIC");
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach