Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    uint8_t x=0,y=0,z=0,i;
    while (str[i] != '\0') {
        if (str[i] >= '0' && str[i] <= '9') {
            x = 1;
        } else if((str[i] >= 'A' && str[i] <= 'Z') ||
                   (str[i] >= 'a' && str[i] <= 'z'))
        {
           y=1;
        } else {
           z = 1;
        }
        i++;
    }
    if (z || (x && y)) {
        printf("MIXED\n");
    } else if (x) {
        printf("NUMERIC\n");
    } else if (y) {
        printf("ALPHABETIC\n");
    } else {
        printf("MIXED\n"); // Covers empty string or unexpected cases
    }


}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach