Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    int num,alp,count=0;
    for(int i=0;str[i]!='\0';i++){
        int t=str[i];
        if((t>=48)&&(t<=57)){
        num++;
    }
    else if(((t>=65)&&(t<=90))||((t>=97)&&(t<=122))){
        alp++;
    }
    count++;
    }
    if(num==count){printf("NUMERIC");}
    else if(alp==count){printf("ALPHABETIC");}
    else printf("MIXED");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach