Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    int has_digit = 0;
    int has_alpha = 0;

    /* Empty string check */
    if (str[0] == '\0') {
        printf("MIXED\n");
        return;
    }

    for (int i = 0; str[i] != '\0'; i++) {
        char c = str[i];

        /* Digit check */
        if (c >= '0' && c <= '9') {
            has_digit = 1;
        }
        /* Alphabet check */
        else if ((c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z')) {
            has_alpha = 1;
        }
        /* Any other character */
        else {
            printf("MIXED\n");
            return;
        }

        /* Early exit if both found */
        if (has_digit && has_alpha) {
            printf("MIXED\n");
            return;
        }
    }

    if (has_digit)
        printf("NUMERIC\n");
    else if (has_alpha)
        printf("ALPHABETIC\n");
    else
        printf("MIXED\n");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach