Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    uint8_t a = 0;
    uint8_t n = 0;
    uint8_t s = 0;
     while(*str){
        if(((*str >= 'A') && (*str <='Z')) || ((*str >= 'a') && (*str <='z'))){
             a++;
        }
        else {
            if((*str >= '0') && (*str <='9')){
                 n++;
            }
            else {
                if (!(*str==' ')) s++;
            }
        }
       
        str++;
    }
    if ((a && n) || s) printf("MIXED\n");
    else if (a && !n) printf("ALPHABETIC\n");
    else printf("NUMERIC\n");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach