Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    int digit=0;
    int letter=0;
    int symbol=0;
    int end=0;
    while(str[end] != '\0'){
        if((str[end] >= 'A' && str[end] <= 'Z') || (str[end] >= 'a' && str[end] <= 'z')) letter++;
        else if((str[end] >= '0' && str[end] <= '9')) digit++;
        else symbol++;
        end++;
    }
    if(letter==0 && symbol==0) printf("NUMERIC");
    else if(digit==0 && symbol==0) printf("ALPHABETIC");
    else printf("MIXED");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

 

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Input

123456

Expected Output

NUMERIC