Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    int alpha = 0;
    int digit = 0;
    int mixed = 0;
    while(*str !='\0' ){
        if((*str >= '0') && (*str <= '9'))  digit++;
        else if (((*str >= 'A') && (*str <= 'Z')) || ((*str >= 'a') && (*str <= 'z'))) alpha++;
        else mixed++;

        str++;
    }
    if (mixed >0) printf("MIXED");
    else if ((digit > 0) && (alpha == 0)) printf("NUMERIC");
    else if ((alpha > 0) && (digit == 0)) printf("ALPHABETIC");
    else printf("MIXED");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach