99. Check if the String Numeric or Alphabetic

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Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
        int i = 0;
    int has_digit = 0;
    int has_alpha = 0;

    // Check empty string
    if(str[0] == '\0')
    {
        printf("MIXED\n");
        return;
    }

    while(str[i] != '\0')
    {
        if(str[i] >= '0' && str[i] <= '9')
        {
            has_digit = 1;
        }
        else if((str[i] >= 'A' && str[i] <= 'Z') || 
                (str[i] >= 'a' && str[i] <= 'z'))
        {
            has_alpha = 1;
        }
        else
        {
            printf("MIXED\n");
            return;
        }

        i++;
    }

    if(has_digit && !has_alpha)
        printf("NUMERIC\n");
    else if(has_alpha && !has_digit)
        printf("ALPHABETIC\n");
    else
        printf("MIXED\n");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

 

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