Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>
#include <string.h>
//#define s str

void classify_string(const char *str) {
    // Your logic here
    int i,j,n=0,y=0;
    int count=strlen(str);
    if((str[0]>='0')&&(str[0]<='9')){
        for(i=0;str[i];i++){
            if((str[i]>='0')&&(str[i]<='9'))
            n++;}
            if(n==(count))
            printf("NUMERIC");
            else
            printf("MIXED");
 }
    else if(((str[0]>='a')&&(str[0]<='z'))||((str[0]>='A')&&(str[0]<='Z'))){
        for(i=0;str[i];i++){
            if(((str[i]>='a')&&(str[i]<='z'))||((str[i]>='A')&&(str[i]<='Z'))){
                y++;
            }
        }
        if(y==(count))
        printf("ALPHABETIC");
        else
        printf("MIXED");
        
    }
    else
    printf("MIXED");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach