Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    uint8_t countDigits=0;
    uint8_t countLetters=0;
    uint8_t countMixed=0;
    while(*str)
    {
        if(*str>='0'&&*str<='9')
        {
            countDigits++;
        }
        else if((*str>='A' && *str <='Z') || (*str>='a' && *str<='z'))
        {
            countLetters++;
        }
        else
        {
            countMixed++;
        }
        str++;
    }
    if(countDigits>0 && countLetters==0 && countMixed==0)
    {
        printf("NUMERIC");
    }
    else if(countLetters>0 && countDigits==0 && countMixed==0)
    {
        printf("ALPHABETIC");
    }
    else{ printf("MIXED");}
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach