Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>


void classify_string(const char *str) {
    // Your logic here
    if(str[0]=='\0') printf("MIXED");
    bool alp = false;
    bool num = false;
    bool mix = false;
    int i=0;
    while(!mix && str[i]!='\0'){
        if(str[i]>='0' && str[i]<='9'){
            if(alp) mix = true;
            num=true;
        }
        else if((str[i]>='a' && str[i]<='z') || (str[i]>='A' && str[i]<='Z')){
            if(num) mix=true;
            alp=true;
        }
        else{
            mix = true;
        }
        i++;
    }
    if(mix) printf("MIXED");
    else if(alp) printf("ALPHABETIC");
    else  printf("NUMERIC");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach