Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

#define NUM_ZERO ('0')
#define NUM_NINE ('9')
#define CHAR_A ('A')
#define CHAR_Z ('Z')
#define CHAR_a ('a')
#define CHAR_z ('z')

#define IS_NUMERIC(chr) ((chr) >= NUM_ZERO && (chr) <= NUM_NINE)
#define IS_ALPHA(chr) (((chr) >= CHAR_A && (chr) <= CHAR_Z) || ((chr) >= CHAR_a && (chr) <= CHAR_z))

void classify_string(const char *str) {
    // Your logic here
    int num_count=0;
    int alpha_count=0;
    while((*str)&&
        ((0 == num_count)||(0 == alpha_count))){
        if(IS_NUMERIC(*str)){
            num_count++;
        }
        else if(IS_ALPHA(*str)){
            alpha_count++;
        }
        else{
            num_count++;
            alpha_count++;
        }
        str++;
    }
    if((0 != num_count)&&(0 == alpha_count)){
        printf("NUMERIC");
    }
    else if((0 == num_count)&&(0 != alpha_count)){
        printf("ALPHABETIC");
    }
    else{
        printf("MIXED");
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach