Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    char state;
    int i = 0;

    if(str[i] >= '0' && str[i] <= '9'){
        state = 'n';
    }
    else{
        state = 'a';
    }

    while(str[i] != '\0'){

        if((str[i] >= '0' && str[i] <= '9')){
            if(state == 'n'){
            state = 'n';
            i++;
            }
            else{
                state = 'm';
                printf("MIXED\n");
                break;
            }
            
        }

        else if((str[i] >= 'A' && str[i] <= 'Z') || (str[i] >= 'a' && str[i] <= 'z')){

            if(state == 'a'){
                state = 'a';
                i++;
            }
            else{
                state = 'm';
                printf("MIXED\n");
                break;
            }
            
        }

        else{
            state = 'm';
            printf("MIXED\n");
            break;
        }


    }

    if(state == 'n'){
        printf("NUMERIC\n");
    }
    else if(state == 'a'){
        printf("ALPHABETIC\n");
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach