Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    int digit,alpha=0,symbol=0;
    int i=0;
    while(str[i]!='\0')
    {
        if(str[i]>='0' && str[i]<='9')
        {
            digit++;
        }
        else if((str[i]>='a' && str[i] <= 'z') || (str[i]>='A' && str[i] <= 'Z'))
        {
            alpha++;
        }
        else{
            symbol++;
        }
        i++;
    }
    if(digit==0 && alpha !=0 && symbol == 0) printf("ALPHABETIC");
    else if(digit!=0 && alpha ==0 && symbol==0)printf("NUMERIC");
    else if((digit!=0 && symbol !=0)||(alpha!=0 && symbol!=0))printf("MIXED");
    else printf("MIXED");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

 

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Input

123456

Expected Output

NUMERIC