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Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    int alpha=0;
    int digit=0;
    int symbol=0;
    int length=0;
    while(*str!='\0'){
        if((*str>='A') && (*str<='Z') || (*str>='a') && (*str<='z')){
            alpha+=1;
        }
        else if(*str>='0' && *str<='9'){
            digit+=1;
        }
        else{
            symbol+=1;
        }
        str++;
        length++;
    }
    if(alpha==length){
        printf("ALPHABETIC");
    }
    else if(digit==length){
        printf("NUMERIC");
    }
    else{
        printf("MIXED");
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

simple conditional statements

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Input

123456

Expected Output

NUMERIC