Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here

    int has_digit = 0;
    int has_alpha = 0;
    int has_other = 0;

    int i = 0;

     while (str[i] != '\0') {
        char ch = str[i];

        if (ch >= 48 && ch <= 57) {
            has_digit = 1;
        }
        else if ((ch >= 65 && ch <= 90) || (ch >= 97 && ch <= 122)) {
            has_alpha = 1;
        }
        else {
            has_other = 1;
        }

        i++;
    }

    if (has_other || (has_digit && has_alpha)) {
        printf("MIXED");
    }
    else if (has_digit) {
        printf("NUMERIC");
    }
    else if (has_alpha) {
        printf("ALPHABETIC");
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach