Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>
#include <string.h>
void classify_string(const char *str) {
    // Your logic here
    int n=strlen(str);
    int a=1;
    int num=1;
    for(int i=0;i<n;i++)
    {
        if(str[i]>='0' && str[i]<='9')
        a=0;
        else if((str[i]>='a'&&str[i]<='z')||(str[i]>='A'&&str[i]<='Z'))
        num=0;
        else
        {
            a=0;
            num=0;
        }
    }
    if(a==1 && num==1)
    printf("MIXED");
    else if(a==0 &&  num==1)
    printf("NUMERIC");
    else if(a==1 && num==0)
    printf("ALPHABETIC");
    else
    printf("MIXED");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

 

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Input

123456

Expected Output

NUMERIC