99. Check if the String Numeric or Alphabetic

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Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    uint8_t dig=0,alpha=0,index=0;

     if (str[0] == '\0') {
        printf("MIXED");  // Empty string treated as mixed
        return;
    }
    while(str[index]!='\0')
    {
        if(str[index]>='0' && str[index]<='9')
            dig=1;
        else if((str[index]>='A' && str[index]<='Z') || (str[index]>='a' && str[index]<='z') )
            alpha=1;
        else 
        {
            printf("MIXED");
            return;
        }
        index++;
    }

    if(dig==1 && alpha==0)
        printf("NUMERIC");
    else if(alpha==1 && dig==0)
        printf("ALPHABETIC");
    else 
        printf("MIXED");
}   

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

 

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