Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    if(*str == '\0'){
        printf("MIXED");
        return;
    }
        

    uint8_t num[3]={0};      //0->mixed,1->decimal,2->alphabetic
    uint8_t i=0;

    while(*(str+i)!='\0'){
        char ch=*(str+i);
        if (ch>='0' && ch<='9')
            num[2]=1;
        else if ((ch>='A' && ch<='Z') || ch>='a' && ch<='z')
            num[1]=1;
        else
            num[0]=1;
        i++;
    }
    


    if(num[0] || num[1] && num[2])
        printf("MIXED");
    else if(num[2]==1)
        printf("NUMERIC");
    else  
        printf("ALPHABETIC");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach