Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    int id=0;
    for(int i=0;str[i];i++){
        if(str[i]>='0' && str[i]<='9'){
            if(id==0 || id==1){
                id=1;
            }
            else{
                printf("MIXED");
                id=0;
                break;
            }
        }
        else if((str[i]>='A' && str[i]<='Z') || (str[i]>='a' && str[i]<='z')){
            if(id==0 || id==2){
                id=2;
            }
            else{
                printf("MIXED");
                id=0;
                break;
            } 
        }
        else{
            printf("MIXED");
            id=0;
            break;
        }
    }
    if(id) id==1 ? printf("NUMERIC") : printf("ALPHABETIC");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach