Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    int has_digit = 0;
    int has_alpha = 0;
    int has_other = 0;

    for (int i = 0; str[i] != '\0'; i++) {
        if (str[i] >= '0' && str[i] <= '9') {
            has_digit = 1;
        } 
        else if ((str[i] >= 'A' && str[i] <= 'Z') || 
                 (str[i] >= 'a' && str[i] <= 'z')) {
            has_alpha = 1;
        } 
        else {
            has_other = 1;
        }
    }

    int kinds = has_digit + has_alpha + has_other;

    if (kinds >= 2) {
        printf("MIXED\n");
    } 
    else if (has_digit) {
        printf("NUMERIC\n");
    } 
    else if (has_alpha) {
        printf("ALPHABETIC\n");
    } 
    else {
        printf("MIXED\n"); // Only symbols or empty string
    }

}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach