Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>
#include <string.h>

void classify_string(const char *str) {
    // Your logic here
    int l=strlen(str);
int n=0,a=0;
    for(int i=0;i<l;i++){
        if(str[i]>='0'&&str[i]<='9'){
         n++;
        }
       else if((str[i]>='a'&&str[i]<='z')||(str[i]>='A'&&str[i]<='Z')){
         a++;
        }
        

    }
    if(l==n){
        printf("NUMERIC");
    }else if(l==a){printf("ALPHABETIC");
    }else{printf("MIXED");}
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach