99. Check if the String Numeric or Alphabetic

Back To All Submissions
Previous Submission
Next Submission

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    if(str[0] == 0){
        printf("MIXED");
        return;
    }
    int NC = 0, CC = 0, OC = 0;
    for(int i=0;str[i] != 0;i++){
        if(str[i]>= '0' && str[i]<='9')
            NC++;
        else if((str[i]>= 'a' && str[i]<='z') || (str[i]>= 'A' && str[i]<='Z'))
            CC++;
        else    
            OC++;
    }
    if( (OC>=1) || (NC*CC >= 1)) printf("MIXED");
    else if(CC + NC == CC) printf("ALPHABETIC");
    else if(NC + CC == NC) printf("NUMERIC");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

 

Was this helpful?
Upvote
Downvote