Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    int i,d_count=0,a_count=0,s_count=0;
    for(i=0;str[i];i++)
    {
        if(str[i]=='\0')
        {
            printf("mixed");
        }
        else if(str[i]>='0' && str[i]<='9')
        {
            d_count++;
        }
        else if((str[i]>='a' && str[i]<='z')|| (str[i]>='A' && str[i]<='Z'))
        {
            a_count++;
        }
        else
            s_count++;
    }
    if((d_count==0 && a_count>=0 && s_count ==0) ){
        printf("ALPHABETIC");
    }
    else if(d_count>=0 && a_count==0 && s_count ==0){
        printf("NUMERIC");
    }
    else{
        printf("MIXED");
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach