Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    int cnt = 0;
    int classify = 0; 
    while(str[cnt]!=0){
        if(str[cnt]>='0' && str[cnt]<='9'){
            if(classify ==2){
                printf("MIXED");
                classify = 0;
                break;
            }
            else{
                classify = 1;
            }
        }
        else if((str[cnt]>='a' && str[cnt]<='z') || (str[cnt]>='A' && str[cnt]<='Z')){
            if(classify ==1){
                printf("MIXED");
                classify = 0;
                break;
            }
            else{
                classify = 2;
            }
        }
        else{
           printf("MIXED");
           classify =0;
           break;
        }
        cnt++;
    }
    if(classify == 1){
        printf("NUMERIC");
    }
    else if(classify ==2){
        printf("ALPHABETIC");
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

 

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Input

123456

Expected Output

NUMERIC