Circular Buffer Read

Code

#include <stdio.h>

typedef struct {
    int buffer[10];
    int head;
    int tail;
    int count;
    int capacity;
} CircularBuffer;

void read_bytes(CircularBuffer *cb, int n) {
    // Your logic here
    int i;
    for (i=0; i < n; i++) {
        if (i > 0) 
            printf(" "); // formatting the number to exapected

        if (cb->count >0) {
            printf("%d", cb->buffer[cb->tail]);
            cb->tail = (cb->tail + 1) % 10;
            cb->count--;
        }
        else {
            printf("NULL");
        }
    }
    printf("\n");
    printf("Tail: %d", cb->tail);
}

int main() {
    CircularBuffer cb = {
        .buffer = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100},
        .head = 3,
        .tail = 7,
        .count = 6,
        .capacity = 10
    };

    int n;
    scanf("%d", &n);
    read_bytes(&cb, n);

    return 0;
}

Solving Approach

The challenge here was in formatting the printed numbers to account for the spaces