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Circular Buffer Read

Code

#include <stdio.h>

typedef struct {
    int buffer[10];
    int head;
    int tail;
    int count;
    int capacity;
} CircularBuffer;

void read_bytes(CircularBuffer *cb, int n) {
    // Your logic here
    int c=0;
    while(c<n){
        if(cb->count==0){
        printf("NULL");
        }
        else{
            
            printf("%d",cb->buffer[cb->tail]);
            cb->tail=(cb->tail+1)%cb->capacity;
            cb->count--;
        }
        if(c!=n-1){
            printf(" ");
        }
        c++;
    }
    printf("\nTail: %d",cb->tail);
}

int main() {
    CircularBuffer cb = {
        .buffer = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100},
        .head = 3,
        .tail = 7,
        .count = 6,
        .capacity = 10
    };

    int n;
    scanf("%d", &n);
    read_bytes(&cb, n);

    return 0;
}

Solving Approach

 

simple circular buffer and pointer concepts helped me to solve the problem

 

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Input

4

Expected Output

80 90 100 10 Tail: 1