Clear Specific Bits in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t clear_bits(uint32_t reg, uint8_t pos, uint8_t len) {
    // Your code here
    int mask = 0;
    for(int i=0;i<len;i++){
        mask = mask | (1<<i) ;
    }
    mask = mask << pos;
    return reg = reg & (~mask);
}

int main() {
    uint32_t reg;
    uint8_t pos, len;
    scanf("%u %hhu %hhu", &reg, &pos, &len);
    printf("%u", clear_bits(reg, pos, len));
    return 0;
}

Solving Approach

#include <stdio.h>
#include <stdint.h>

uint32_t clear_bits(uint32_t reg, uint8_t pos, uint8_t len) {
    // Your code here
    int mask = 0;
    for(int i=0;i<len;i++){
        mask = mask | (1<<i) ;
    }
    mask = mask << pos;
    return reg = reg & (~mask);
}

int main() {
    uint32_t reg;
    uint8_t pos, len;
    scanf("%u %hhu %hhu", &reg, &pos, &len);
    printf("%u", clear_bits(reg, pos, len));
    return 0;
}

consider example 1.

Input: reg = 0b1111 1111, pos = 4, len = 4 
Output: 0b0000 1111

 1.  for(int i=0;i<len;i++){
        mask = mask | (1<<i) ;
    }
    
    iterating the loop left shifting or(|) operation with the mask.
    
 2.	mask = mask << pos --> mask value rightshifting to position to value.
 
 3. reg = reg & (~mask)  --> complementing the mask value and (&) operation  with reg