Clear Specific Bits in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t clear_bits(uint32_t reg, uint8_t pos, uint8_t len) {
    // Your code here
    uint8_t i;
    for(i=0; i<len; i++)
    {
        reg=reg& (~(1<<(pos+i)));
    }
    return reg;
}

int main() {
    uint32_t reg;
    uint8_t pos, len;
    scanf("%u %hhu %hhu", &reg, &pos, &len);
    printf("%u", clear_bits(reg, pos, len));
    return 0;
}

Solving Approach

I used simple logic, basic code, can be optimized.