Clear the Bit in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t clear_bit(uint8_t reg, uint8_t pos) {
    // Create a mask with 1 at the bit position and invert it, then AND with reg
        reg = reg & ~(1 << pos);
            return reg;
            }

            int main() {
                uint8_t reg, pos;
                    scanf("%hhu %hhu", &reg, &pos);
                        uint8_t result = clear_bit(reg, pos);
                            printf("%u", result);
                                return 0;
                                }

Solving Approach