Clear the Bit in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t clear_bit(uint8_t reg, uint8_t pos) {
    // Your code here
    reg = reg & ~(1<<pos);
    return reg;
}

int main() {
    uint8_t reg, pos;
    scanf("%hhu %hhu", &reg, &pos);
    uint8_t result = clear_bit(reg, pos);
    printf("%u", result);
    return 0;
}

Solving Approach

uint8_t clear_bit(uint8_t reg, uint8_t pos) {
    // Your code here
    reg = reg & (~(1<<pos));
    return reg;
}

consider example 2
Input: reg = 0000 1111, pos = 3 
Output: 0000 0111

1. (1<<pos) :- 1 left shifting specific position
2. (~(1<<pos)) :- (1<<pos) this position bit complementing 
	0000 1111	-> (1<<pos)
	0000 0111	-> (~(1<<pos))
	
3. reg & (~(1<<pos)) :- reg & operation

	0000 1111	-> reg
	0000 0111	-> (~(1<<pos))
	----------
	0000 0111	-> result
	----------