Clear the Bit in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t clear_bit(uint8_t reg, uint8_t pos) {
    // Your code here
    return reg&=~(1<<pos);
}

int main() {
    uint8_t reg, pos;
    scanf("%hhu %hhu", &reg, &pos);
    uint8_t result = clear_bit(reg, pos);
    printf("%u", result);
    return 0;
}

Solving Approach

reg =8 pos=3
1<<pos
00001000
~(1<<pos)
00000000
reg & = ~(1<<pos)
00001000
00000000
-------------------
00000000
so bit is cleared