Construct UART Data Frame with Parity Bit

Code

#include <stdio.h>
#include <stdint.h>

typedef struct {
    uint8_t parity_enable : 1;
    uint8_t parity_type   : 1;
    uint8_t reserved      : 6;
} UART_Control;
 
 uint8_t count_no_ones(uint8_t data)
 {
    int num=data;
    int count=0;
    while(num>0)
    {
        if(num & 1)
        {
            count++;
        }
    num=num>>1;
    }
    return count;
 }
uint8_t create_uart_frame(uint8_t data, UART_Control *ctrl) {
    // Your logic here
    //firstly i will check the parity enable bit
    uint8_t frame;
    if(ctrl->parity_enable ==0)
    {
        frame=(0U<<7)|data;
    }
    else
    {
        uint8_t ones=count_no_ones(data);
        uint8_t parity_bit;
        if(ctrl->parity_type == 0)
        {
           parity_bit = (ones % 2 == 0)?0:1;
        }
        else
        {
            parity_bit = (ones % 2 == 0)?1:0;
        }

            
    frame=(parity_bit<<7)|data;

    }
    return frame;
}

int main() {
    uint8_t data;
    scanf("%hhu", &data);  // 7-bit input

    uint8_t parity_enable, parity_type;
    scanf("%hhu %hhu", &parity_enable, &parity_type);

    UART_Control ctrl;
    ctrl.parity_enable = parity_enable;
    ctrl.parity_type = parity_type;

    uint8_t frame = create_uart_frame(data, &ctrl);
    printf("frame = 0x%02X", frame);

    return 0;
}

Solving Approach