Construct UART Data Frame with Parity Bit

Code

#include <stdio.h>
#include <stdint.h>

typedef struct {
    uint8_t parity_enable : 1;
    uint8_t parity_type   : 1;
    uint8_t reserved      : 6;
} UART_Control;

int sum_of_one(uint8_t data){
    int count;
    for(int i=0;i<7;i++){
        if((data & (1 << i)) != 0)
            count++;
    }
    return count;
}

uint8_t create_uart_frame(uint8_t data, UART_Control *ctrl) {
    // Your logic here
    data |= 0x00; // convert 7-bit data into 8-bit
    if(ctrl -> parity_enable == 0)
        return data;
    int ones;
    ones = sum_of_one(data);
    if(ctrl -> parity_type == 1){
        if(ones % 2 == 0)
            return data | (1 << 7);
        else
            return data;
    }
    else{
        if(ones % 2 == 0)
            return data;
        else
            return data | (1 << 7);
    }
    return 0;
}

int main() {
    uint8_t data;
    scanf("%hhu", &data);  // 7-bit input

    uint8_t parity_enable, parity_type;
    scanf("%hhu %hhu", &parity_enable, &parity_type);

    UART_Control ctrl;
    ctrl.parity_enable = parity_enable;
    ctrl.parity_type = parity_type;

    uint8_t frame = create_uart_frame(data, &ctrl);
    printf("frame = 0x%02X", frame);

    return 0;
}

Solving Approach