Construct UART Data Frame with Parity Bit

Code

#include <stdio.h>
#include <stdint.h>

typedef struct {
    uint8_t parity_enable : 1;
    uint8_t parity_type   : 1;
    uint8_t reserved      : 6;
} UART_Control;

uint8_t create_uart_frame(uint8_t data, UART_Control *ctrl) {
    // Your logic here

    int count=0;
    int result;
    if(ctrl->parity_enable ==0)
    {
        return data;
    }
    else if(ctrl->parity_enable ==1)
      {
        for(int i=0; i<=7; i++)
        {
            if((data & (1<<i)))
            count++;
               
        }
       // printf("%d", count);
        if((ctrl->parity_type ==0) )
        {
            if(count%2 ==0)
            ctrl->parity_type =0;
            else
            ctrl->parity_type =1;
        }
        else if (ctrl->parity_type ==1)
        {
            if(count%2 ==0)
            ctrl->parity_type =1;
            else
            ctrl->parity_type =0;
        }

       // result |= data;
       //data |= ctrl->parity_enable<<8;
         data |= ctrl->parity_type<< 7;
       // printf("data %d", data);
        return data;  

      }

    
}

int main() {
    uint8_t data;
    scanf("%hhu", &data);  // 7-bit input

    uint8_t parity_enable, parity_type;
    scanf("%hhu %hhu", &parity_enable, &parity_type);

    UART_Control ctrl;
    ctrl.parity_enable = parity_enable;
    ctrl.parity_type = parity_type;

    uint8_t frame = create_uart_frame(data, &ctrl);
    printf("frame = 0x%02X", frame);

    return 0;
}

Solving Approach