Construct UART Data Frame with Parity Bit

Code

#include <stdio.h>
#include <stdint.h>

typedef struct {
    uint8_t parity_enable : 1;
    uint8_t parity_type   : 1;
    uint8_t reserved      : 6;
} UART_Control;

uint8_t count_data_bits(uint8_t data){
    uint8_t count = 0;
    for(int i=7;i>=0;i--){
        if(data>>i&1)
            count++;
    }
     return count;
}

uint8_t create_uart_frame(uint8_t data, UART_Control *ctrl) {
    // Your logic here
    if(ctrl->parity_enable == 0)    // Checking the parity_enable
        return data;

    int count = 0;
    count = count_data_bits(data);  // counting the set bits in data

    if(ctrl->parity_type == 1){     // checking the parity_type is odd 
        if( count % 2 == 0)         // checking the count even  
        data |= 1<<7;               // if count is even setting parity bit is 1
        else                        
        data &= ~(1<<7);            // if count is odd setting parity bit is 0
    }
    else if (ctrl->parity_type == 0){   // checking the parity_type is even
        if(count % 2 == 0)              // checking the count even
        data &= ~(1<<7);                // if count is odd setting parity bit is 0
        else
        data |= (1<<7);                 // if count is even setting parity bit is 1
    }
    return data;                // return the data

}

int main() {
    uint8_t data;
    scanf("%hhu", &data);  // 7-bit input

    uint8_t parity_enable, parity_type;
    scanf("%hhu %hhu", &parity_enable, &parity_type);

    UART_Control ctrl;
    ctrl.parity_enable = parity_enable;
    ctrl.parity_type = parity_type;

    uint8_t frame = create_uart_frame(data, &ctrl);
    printf("frame = 0x%02X", frame);

    return 0;
}

Solving Approach