Construct UART Data Frame with Parity Bit

Code

#include <stdio.h>
#include <stdint.h>
#define Clearbit(x,n)(~((1U) << n) & x)
#define SET_BIT(x,n)        ((x) |  (1U << (n)))


typedef struct {
    uint8_t parity_enable : 1;
    uint8_t parity_type   : 1;
    uint8_t reserved      : 6;
} UART_Control;

uint8_t create_uart_frame(uint8_t data, UART_Control *ctrl) {
    // Your logic here
uint8_t par = ctrl ->parity_enable;
uint8_t frame = data;
if(par == 0){frame = Clearbit(frame,7);}

if(par == 1){
uint8_t count = 0;
for (int i=0;i<7;i++){
    uint8_t countermask = (1U);
    if ((countermask & (data >> i)) == 1){
        count ++;
    }
}
switch(ctrl->parity_type){
    case 0:
    if (count % 2 ==0){frame = Clearbit(frame,7);}
    else {frame = SET_BIT(frame,7);}
    break;
    case 1:
    if (count % 2 ==0){frame = SET_BIT(frame,7);}
    else {frame = Clearbit(frame,7);}
    break;
    default:
    break;
}

}
    return frame;
}

int main() {
    uint8_t data;
    scanf("%hhu", &data);  // 7-bit input

    uint8_t parity_enable, parity_type;
    scanf("%hhu %hhu", &parity_enable, &parity_type);

    UART_Control ctrl;
    ctrl.parity_enable = parity_enable;
    ctrl.parity_type = parity_type;

    uint8_t frame = create_uart_frame(data, &ctrl);
    printf("frame = 0x%02X", frame);

    return 0;
}

Solving Approach

 

 

 

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Input

85 1 0

Expected Output

frame = 0x55