Construct UART Data Frame with Parity Bit

Code

#include <stdio.h>
#include <stdint.h>

typedef struct {
    uint8_t parity_enable : 1;
    uint8_t parity_type   : 1;
    uint8_t reserved      : 6;
} UART_Control;

int count_ones(uint8_t data){
    int count =0;
    for(int i = 0; i < 7; i++){
        if((data >> i) & 1){
            count++;
        }
    }
    return count;
}

uint8_t create_uart_frame(uint8_t data, UART_Control *ctrl) {
    // Your logic here
    data = data & 0x7F;
    int parity_bit;
    if(ctrl->parity_enable == 0){
       return data;
    }
    if(ctrl->parity_type == 0){
        int count = count_ones(data);
        if(count % 2 == 0){
            parity_bit = 0;
           return (parity_bit << 7) | data;
        }else{
            parity_bit = 1;
           return (parity_bit << 7) | data;
        }
    }else{
        parity_bit = 1;
        return (parity_bit << 7) | data;
    }
}

int main() {
    uint8_t data;
    scanf("%hhu", &data);  // 7-bit input

    uint8_t parity_enable, parity_type;
    scanf("%hhu %hhu", &parity_enable, &parity_type);

    UART_Control ctrl;
    ctrl.parity_enable = parity_enable;
    ctrl.parity_type = parity_type;

    uint8_t frame = create_uart_frame(data, &ctrl);
    printf("frame = 0x%02X", frame);

    return 0;
}

Solving Approach