Construct UART Data Frame with Parity Bit

Code

#include <stdio.h>
#include <stdint.h>
#define check_bit(n, pos) ((n >> pos)&0x01)
typedef struct {
    uint8_t parity_enable : 1;
    uint8_t parity_type   : 1;
    uint8_t reserved      : 6;
} UART_Control;

uint8_t count_setbit(uint8_t data)
{
    uint8_t count = 0;
    uint8_t temp = data;
    while(temp) 
    {
        if(check_bit(temp, 0))
        {
            count++;
        }
        temp>>=1;
    }
    return count;
}
uint8_t create_uart_frame(uint8_t data, UART_Control *ctrl) {
    // Your logic here
    uint8_t counts = 0;
    uint8_t parity_bit = 0;
    data &=0x7F;
    if(ctrl->parity_enable == 0)
    {
        return data;
    }
    counts = count_setbit(data); 
    if(ctrl->parity_type == 0)
    {
        if(counts % 2 == 0)
        {
            parity_bit = 0;
        }
        else
        {
            parity_bit = 1;
        }
    }
    else
    {
        if(counts % 2 == 1)
        {
            parity_bit = 0;
        }
        else
        {
            parity_bit = 1;
        }
    }
    return (parity_bit << 7)|data;
}

int main() {
    uint8_t data;
    scanf("%hhu", &data);  // 7-bit input

    uint8_t parity_enable, parity_type;
    scanf("%hhu %hhu", &parity_enable, &parity_type);

    UART_Control ctrl;
    ctrl.parity_enable = parity_enable;
    ctrl.parity_type = parity_type;

    uint8_t frame = create_uart_frame(data, &ctrl);
    printf("frame = 0x%02X", frame);

    return 0;
}

Solving Approach