Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int decindx = 0,i=0,num = 0,sign = 1;
    if(str[i] == '-'){
        sign = -1;i++;
    }else if(str[i] == '+'){i++;}
    while(str[i] != '\0'){
        if(str[i] == '.'){
            decindx = 1;
        }else{
            num = num*10+(str[i]-'0');
            decindx *= 10;
        }
        i++;
    }
    decindx = (decindx == 0)?1:decindx;
    return (float)(sign*num)/(float)(decindx);
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach