Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    float result=0;
    int i=0;
    int found_dec=0;
    float frac_divisor=1;
    int sign=(str[0]=='-')?-1:1 ;
    while(str[i]!='\0')
    {
        if(str[i]=='-'||str[i]=='+'){
          ++i;
        }
        if(str[i]=='.'){
            found_dec=1;
            ++i;
        }
        if(found_dec==1){
         frac_divisor=frac_divisor*10;
         result=result + ((str[i]-'0')/frac_divisor);
        }
        else{
            result=10*result+(str[i]-'0');
        }
        
        i++;
    }
    return sign*result;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach

 

 

 

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Input

123.45

Expected Output

123.45