Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    float sign = 1.0f;
    float num = 0.0f;

    if (*str == '-') {
        sign = -1.0f;
        str ++;
    } else if (*str == '+') {
        sign = 1.0f;
        str ++;
    }

    while (*str >= '0' && *str <= '9'){
        num = num * 10.0f + (*str - '0');
        str ++;
    }

    if(*str == '.') {
        str ++;
    }

    float divisor = 10.0f;
    while (*str >= '0' && *str <= '9'){
        num = num + (*str - '0') / divisor;
        str ++;
        divisor *= 10.0f;
        }

    return num*sign;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach