Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    float sign=1;
    int i=0;
    float num=0.0;
    int count=0;
    if(str[i]=='-'){
        sign = -1;
        i++;
    }
    else if(str[i]=='+')
        i++;
    while(str[i]!='\0'){
        if(str[i]=='.'){
            for(int j=i+1;str[j]!='\0';j++)
                count++; // count number of decimal place
        }
        else
            num = num*10.0 + (str[i] - '0');
        i++;
    }
    for(int k=0;k<count;k++) // float value = sum of all string num / 10^(number of decimal place)
        num = num / 10.0;
    return sign * num;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach