Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    float result = 0.0f;
    float divisor = 10.0f;
    int sign = 1;
    uint8_t i = 0;
    uint8_t in_fraction = 0;

    if (str[i] == '+') {
        i++;
    } else if (str[i] == '-') {
        sign = -1;
        i++;
    }

    char c;
    while (c = str[i]) {
        if (c == '.') {
            in_fraction = 1;
            i++;
            continue;
        }

        if ('0' <= c && c <= '9') {
            int digit = c - '0';
            if (in_fraction) {
                result += digit / divisor;
                divisor *= 10.0f;
            } else {
                result = result * 10.0f + digit;
            }
        } else {
            break;
        }
        i++;
    }

    return sign * result;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach