Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>
#include <math.h>

float custom_atof(const char *str) {
    // Your logic here
    int i = 0;
    float val1 = 0;
    float val2 = 0;
    int sign = 1;
    if (str[i] == '-'){
        sign = -1;
        i++;
    }
    if (str[i] == '+'){
        i++;
    }
    while(str[i] != '.' && str[i] != '\0'){
        val1 = val1 * 10 + (str[i] - '0');
        i++;
    }
    if (str[i] != '\0'){
        i++;
        int digits = 1;
        while(str[i]){
            val2 = val2 + pow(0.1, digits) * (str[i] - '0');
            digits++;
            i++;
        }
    }
    return (val1 + val2) * sign;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach