Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    uint8_t i = 0, j = 0, k = 0, left[5], right[5];
    uint8_t hun = 1, is_positive = 1, finished = 0, left_part_finished = 0;
    float dec = 1, number = 0.0;

    if(str[i]=='+')
    {
        i++;
    }
    else if(str[i]=='-')
    {
        i++;
        is_positive = 0;
    }

    while(!finished)
    {
        if(str[i]=='.' || str[i]=='\0')
        {
            if(str[i]=='\0')
                finished = 1;

            while(j>0)
            {
                j--;
                number += (left[j] * hun);
                hun *= 10.0;

                if(j==0)
                    left_part_finished = 1;
            }
            while(k>0)
            {
                k--;
                number += (right[k] * dec);
                dec *= 10;
            }
        }
        else{
            if(!left_part_finished)
                left[j++] = str[i] - '0';
            else
            {
                right[k++] = str[i] - '0';
                dec /= 10.0;
            }
        }
        i++;
    }

    if(!is_positive)
        number *= -1;

    return number;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach