Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    float sign=1.00;
    const char *ch = str;
    if(*ch=='-'){
        sign=-1; 
        ch++;
    }
    else if(*ch == '+') ch++;
    
    float value=0.00;
    while(*ch>='0' && *ch<='9'){
        value=(value*10.00f)+(float)(*ch-'0');
        ch++;
    }
    if(*ch=='.'){//12.12
        ch++;
        float divisor = 10.0f;
        while (*ch >= '0' && *ch <= '9') {
            value += (*ch - '0') / divisor; // 12+1/10
            divisor *= 10.0f; //next loop 12.1+2/100;
            ch++;
        }
    }
    return value*sign;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach