Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    float ans = 0;
    int is_neg = 0,decimal_point = 0, denom = 1;;
    if(*str == '-'){
        is_neg = 1;
        str++;
    }else if(*str == '+'){
        is_neg = 0;
        str++;
    }
    
    while(*str != '\0'){
        if(*str == '.'){
            decimal_point++;
        }else{
            if(decimal_point == 0){
                ans = ans*10 + (*str-'0');
            }else{
               denom*=10;
                ans = ans + ((float)(*str-'0')/denom);
            }
        }
        str++;
    }
    if(is_neg) ans *= -1;
    return ans;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach